Re: doesn't bash do variable subst. or quote removal on function statement

[Linda Walsh]

Chet Ramey wrote:
> No.  The shell doesn't perform any word expansions on the `name' when
> executing a function definition command.  Since the documentation doesn't
> say it performs any expansions, why would you assume it does?
>   
Because it does quote quote removal on other statements that _seem_ to be
of similar syntax.


I.e.:

declare  "ab=1"   "ab"=1   ab"=1"  a"b=1"  "a"b=1   a"b"=1   ab"=1"
 all appear to do quote removal, making them equivalent to
declare ab=1

vs. for function, where
one has:
 function a {(echo hi)}

then one might think, _at least_, that some similar syntax would
work like:

function "a" {(echo hi)}  function "a" "{(echo hi)}"

or even

declare -f a="{(echo hi)}"

_might_ work.

Also, from a documentation standpoint, not all behaviors are documented
in the manpage, like:

echo $[1+2]

as far as I can tell, isn't documented, yet not supporting
its behavior would break many older scripts....