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Re: declare [-+]n behavior on existing (chained) namerefs
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From: |
Chet Ramey |
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Subject: |
Re: declare [-+]n behavior on existing (chained) namerefs |
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Date: |
Thu, 5 May 2016 14:22:15 -0400 |
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User-agent: |
Mozilla/5.0 (Macintosh; Intel Mac OS X 10.10; rv:45.0) Gecko/20100101 Thunderbird/45.0 |
On 4/29/16 12:50 PM, Grisha Levit wrote:
> The only buggy behavior when inside of functions (ignoring scope issues)
> seems to be that `declare -n ref’ unsets the value of $ref if it previously
> pointed to a variable that is unset.
>
> |$ f() { unset var; declare -n ref=var; declare -n ref; declare -p ref; }; f
> declare -n ref # why did the value of ref disappear? $ f() { local var;
> declare -n ref=var; declare -n ref; declare -p ref; }; f declare -n ref="var"
> |
I fixed this as part of making other changes prompted by the discussion.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU chet@case.edu http://cnswww.cns.cwru.edu/~chet/