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Re: IFS boundary behaviour is not consistent passing arguments to a func
Re: IFS boundary behaviour is not consistent passing arguments to a function for bash 4.3 or 4.4 .
Tue, 3 Oct 2017 16:13:11 -0400
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On 10/2/17 11:26 PM, McCue, Glenn (SSC/SPC) wrote:
> The IFS behaves differently depending on how the command is structured.
> This is my test script. It demonstrates the behavior change between 3.2 and
> The function "doit" lists the individual arguments that it has received.
More or less; you need to add quoting.
> The function "doit" is called twice, each time setting IFS.
> The first time the function is called the arguments to "doit" are just listed
> in the function call.
> The second time the function "doit" is called the arguments are concatenated
> in a variable and the variable is used as the argument to the function.
It's clearer if you quote your variable references where you don't want
word splitting to happen ($argv1), but the basic change came between
bash-3.2 and bash-4.0, around January 2009. The bash-3.2 behavior was
IFS characters that aren't part of an expansion should not cause word
splitting. Bash-3.2 had a problem with `:', `=', and `~' (because of how
it did tilde expansion). If those characters are in $IFS, and they don't
result in tilde expansion, they should not cause word splitting.
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU address@hidden http://cnswww.cns.cwru.edu/~chet/