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Re: My script makes a defunct subshell and sticks on read


From: Øyvind Hvidsten
Subject: Re: My script makes a defunct subshell and sticks on read
Date: Wed, 31 Jan 2018 12:09:07 +0100
User-agent: Cathedral Secure Mail v0.8

On 30/01/18 22:54, Øyvind Hvidsten wrote:
> On 30/01/18 22:51, Chet Ramey wrote:
>> On 1/30/18 3:04 PM, Øyvind Hvidsten wrote:
>>
>>> Bash Version: 4.4
>>> Patch Level: 12
>>> Release Status: release
>>>
>>> Description:
>>>      Running the included script, which does nothing useful but is
>>> cut down
>>> a lot to demonstrate the issue, my main computer (amd64 based) counts to
>>> several million, then Bash stops responding, using 100% cpu and ends up
>>> with a defunct subshell. On my Raspberry Pi, running Raspbian Stretch
>>> and
>>> the same version of Bash (4.4.12), the same thing happens after only
>>> a few
>>> thousand iterations.
>>>
>>> Repeat-By:
>>>      for ((i=0; ; i++)); do ((i%100)) || echo $i; exec {fd}<> >(:);
>>> read -t
>>> 0.001 -u $fd; exec {fd}>&-; done
>>
>> In one sense, it's surprising that this works at all. You're opening a
>> file
>> descriptor read-write (and trying to read from it) to a pipe that's
>> opened
>> for writing only (the >(command) form is supposed to be used by processes
>> that write to the resulting file).
>>
> Yes. It's actually a rather neat hack if one wants to sleep without the
> "sleep" command or bash addons. I'm chasing a more complex issue though,
> and I'm wondering if whatever happens here could be happening with
> subshells in general.
>
>

It will also lock up when run like this, without opening and closing the file descriptor repeatedly. A missed signal, perhaps?

exec {fd}<> <(:); for ((i=0; ; i++)); do ((i%100)) || echo $i; read -t 0.001 -u $fd; done

Note I also turned the pipe around so it's opened for read only instead of write :)



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