On Mon, Feb 12, 2018 at 3:23 PM, Nikolai Kondrashov <spbnick@gmail.com
<mailto:spbnick@gmail.com>> wrote:
Take a look at these links:
- http://wiki.bash-hackers.org/commands/builtin/unset
<http://wiki.bash-hackers.org/commands/builtin/unset>
- http://www.fvue.nl/wiki/Bash:_Passing_variables_by_reference
<http://www.fvue.nl/wiki/Bash:_Passing_variables_by_reference>
Thanks, Clark! However, I find it difficult to follow the explanation at the
first link and even more difficult to connect it to this case. So I'm not
sure
I'm getting it right. Could you maybe explain what exactly happens in the
code
I posted?
Your code:
inner() {
unset res
if [[ $1 == "set" ]]; then
res[0]="X"
res[1]="Y"
fi
}
outer() {
local res=
inner "$1"
echo "res: ${res[@]}"
}
The "unset" in inner() actually unsets the "res" in outer() and the
following assignment (to res[0] and res[1]) is actually assigning to the
global var "res". And in outer(), after calling inner(), its local "res" is
gone and it also referencing to the global var "res".
With 2 "unset" commands, even the global "res" is unset.