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Re: Number with sign is read as octal despite a leading 10#


From: Clint Hepner
Subject: Re: Number with sign is read as octal despite a leading 10#
Date: Mon, 9 Jul 2018 21:37:49 -0400

The + is a unary operator, not part of the literal. Write $((+10#0034)) instead.

--
Clint
On Jul 9, 2018, 9:24 PM -0400, Isaac Marcos <address@hidden>, wrote:
> Configuration Information [Automatically generated, do not change]:
> Machine: x86_64
> OS: linux-gnu
> Compiler: gcc
> Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64'
> -DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='x86_64-pc-linux-gnu'
> -DCONF_VENDOR
> uname output: Linux IO 4.9.0-6-amd64 #1 SMP Debian 4.9.88-1+deb9u1
> (2018-05-07) x86_64 GNU/Linux
> Machine Type: x86_64-pc-linux-gnu
>
> Bash Version: 4.4
> Patch Level: 12
> Release Status: release
>
> Description:
> A value inside an arithmetic expansion is processed as octal despite using
> a 10# preffix.
>
> Repeat-By:
> $ echo $((10#+0034))
> 28
>
> Fix:
> Extract optional sign before parsing the number, re-attach after.
>
> --
> Cases are always threesome:
> Best case, Worst case, and Just in case


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