failglob handling

[Thomas Deutschmann]

Hi,

please see the following script:

> #!/bin/bash
> shopt -s failglob
> if [[ $? -ne 0 ]]; then
>         echo 'shopt failed'
>         exit 1
> fi
> 
> # Let's view current options just to be sure
> shopt -p
> 
> # The following glob should fail because /foo/bar does not exist ...
> # Due to 'failglob' option, bash should stop here
> echo /foo/bar/*
> 
> # This code should never run if previous glob failed
> echo Still alive

Is the assumption true that "Still alive" should *never* be printed
when "/foo/bar" does not exist?

With bash 4.4-5 (aka 4.4.12(1)) on Debian Stretch and 4.4.23(1) on Gentoo,
"Still alive" will be printed.

When you add "set -e" to the beginning, execution will stop immediately
after the failing glob, i.e. no "Still alive" will be printed.

However, see the following interesting difference between semicolons and
newlines:

> $ echo "shopt -s failglob; echo /foo/bar/*; echo alive; " | bash
> bash: line 1: no match: /foo/bar/*
> $ echo "shopt -s failglob; echo /foo/bar/*; echo alive; " | sed 's:; :\n:g' | 
> bash
> bash: line 2: no match: /foo/bar/*
> alive
> $ echo "set -e; shopt -s failglob; echo /foo/bar/*; echo alive; " | sed 's:; 
> :\n:g' | bash
> bash: line 3: no match: /foo/bar/*
> $


-- 
Regards,
Thomas Deutschmann / Gentoo Linux Developer
C4DD 695F A713 8F24 2AA1 5638 5849 7EE5 1D5D 74A5

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