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Re: Segfault on recursive trap/kill

From: Chet Ramey
Subject: Re: Segfault on recursive trap/kill
Date: Sat, 6 Oct 2018 12:33:22 -0400
User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.14; rv:52.0) Gecko/20100101 Thunderbird/52.9.1

On 10/5/18 9:33 PM, Mike Gerwitz wrote:
> The following code will cause a segfault on bash-4.4.19(1) on
> GNU Guix.  I reproduced the issue on an old Ubuntu 14.04 LTS running
> bash-4.3.11(1) as well as a Trisquel system running the same version.
>   bash -c 'trap "kill 0" TERM; kill 0'
> Also segfaults when replacing `0' with `$$', and presumably in any other
> situation that would trigger the trap recursively.

Yes. Bash has allowed recursive trap handlers since early 2014 (pre-4.3)
due to requests for the feature and compatibility with other shells that
allow it.

If you manage to create infinite recursion, bash won't stop you.

``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    address@hidden    http://tiswww.cwru.edu/~chet/

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