Re: Problem in var substitution with / and \

[Chet Ramey]

On 1/14/19 6:51 AM, Jean-François Berroyer wrote:

> Bash Version: 5.0
> Patch Level: 0
> Release Status: release
> 
> Description:
> If a variable contains one '/' (or many)
> and if this '/' is escaped with '\' by substitution mechanism
> and if the escaped variable is concatenated with a string containing '/' as
> prefix, and another string containing '/' as suffix
> then all characters in prefix and suffix are escaped with '\'
> The problem does not occurs in a "" context
> 
> Repeat-By:
> URL=http://example.com
> ESCAPED_URL=${URL//\//\\\/}
> echo 'My URL: '$ESCAPED_URL' ... OK'
> echo '/My URL: http:\/\/example.com ... OK/'
> echo "/My URL: $ESCAPED_URL ... OK/"
> echo '/My URL: '$ESCAPED_URL' ... KO/'

See if this fixes it:

http://lists.gnu.org/archive/html/bug-bash/2019-01/msg00087.html

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/