Re: Problem in var substitution with / and \

[Jean-François Berroyer]

On 14/01/2019 15:00, Chet Ramey wrote:
> On 1/14/19 6:51 AM, Jean-François Berroyer wrote:
>
> > Bash Version: 5.0
> > Patch Level: 0
> > Release Status: release
> >
> > Description:
> > If a variable contains one '/' (or many)
> > and if this '/' is escaped with '\' by substitution mechanism
> > and if the escaped variable is concatenated with a string containing '/' as
> > prefix, and another string containing '/' as suffix
> > then all characters in prefix and suffix are escaped with '\'
> > The problem does not occurs in a "" context
> >
> > Repeat-By:
> > URL=http://example.com
> > ESCAPED_URL=${URL//\//\\\/}
> > echo 'My URL: '$ESCAPED_URL' ... OK'
> > echo '/My URL: http:\/\/example.com ... OK/'
> > echo "/My URL: $ESCAPED_URL ... OK/"
> > echo '/My URL: '$ESCAPED_URL' ... KO/'
>
> See if this fixes it:
>
> http://lists.gnu.org/archive/html/bug-bash/2019-01/msg00087.html

I confirm the problem has disappeared in bash 5.0.2
Thanks.