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Can not declare a local variable if an global ro-variable exists with th


From: joergboe
Subject: Can not declare a local variable if an global ro-variable exists with the same name
Date: Wed, 27 Mar 2019 14:06:51 +0100 (CET)

Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64' 
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='x86_64-redhat-linux-gnu' 
-DCONF_VENDOR='redhat' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL 
-DHAVE_CONFIG_H   -I.  -I. -I./include -I./lib   -O2 -g -pipe -Wall 
-Wp,-D_FORTIFY_SOURCE=2 -fexceptions -fstack-protector-strong 
--param=ssp-buffer-size=4 -grecord-gcc-switches   -m64 -mtune=generic
uname output: Linux ocde150562 3.10.0-957.10.1.el7.x86_64 #1 SMP Thu Feb 7 
07:12:53 UTC 2019 x86_64 x86_64 x86_64 GNU/Linux
Machine Type: x86_64-redhat-linux-gnu

Bash Version: 4.2
Patch Level: 46
Release Status: release

Description:
        If I declare a global read-only variable and I try to declare a local 
variable with that name, I can not create
        the local variable.
        I expect that local variables can be declared independently for the 
global variables.

Repeat-By:
        $ declare -r var=55
        $ myfunction() {
        > local var=11
        > echo "\$var=$var"
        > return 0
        > }
        $ myfunction
        bash: local: var: readonly variable
        $var=55





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