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Re: shouldn't it the comma operator has the lowerest precedence in the s
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From: |
hk |
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Subject: |
Re: shouldn't it the comma operator has the lowerest precedence in the shell arithmetic expression? |
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Date: |
Wed, 2 Oct 2019 08:59:41 +0800 |
sorry for the typo in the title, it should be *lowest*.
On Wed, Oct 2, 2019 at 8:35 AM hk <hkadeveloper@gmail.com> wrote:
> Configuration Information :
> Bash Version: 5.0
> Patch Level: 0
> Release Status: release
>
> Description:
> the code snippet from expr.c starting from line 141:
>
>> /* This should be the function corresponding to the operator with the
>> highest precedence. */
>> #define EXP_HIGHEST expcomma
>
>
> Am I understanding it wrong or is it a typo?
>