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Re: ${!variable@operator} does not work for variables without values; i

From: Chet Ramey
Subject: Re: ${!variable@operator} does not work for variables without values; inconsistencies between present and absent [@] for @A and @a
Date: Thu, 20 Feb 2020 15:41:34 -0500
User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.14; rv:68.0) Gecko/20100101 Thunderbird/68.5.0

On 2/19/20 5:22 PM, Arfrever Frehtes Taifersar Arahesis wrote:
>> ${variable@A} does not work for scalar variables without values, but
>> interestingly ${variable[@]@A} works for them.
> More precisely, ${variable[@]@A} is non-empty, but not exactly correct.
>> See difference between ${VAR1@A} and ${VAR1[@]@A} below.
> ${VAR1[@]@A} is:
> declare -rl VAR1=''"
> But should be:
> declare -rl VAR1
> As in output of 'declare -p VAR1'.

The output is two blank lines:

$ cat x6b
declare -lr VAR1

echo ${VAR1@A}
echo ${VAR1[@]@A}
$ ../bash-5.0-patched/bash ./x6b

The question is whether the unset variables should display commands to
set the attributes (@A) or display any attributes (@a).

``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    address@hidden    http://tiswww.cwru.edu/~chet/

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