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Re: No word splitting for assignment-like expressions in compound assign

From: Chet Ramey
Subject: Re: No word splitting for assignment-like expressions in compound assignment
Date: Tue, 28 Jul 2020 17:34:48 -0400
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On 7/28/20 4:14 PM, Ilkka Virta wrote:
> On 28.7. 17:22, Chet Ramey wrote:
>> On 7/23/20 8:11 PM, Alexey Izbyshev wrote:
>>> $ Z='a b'
>>> $ A=(X=$Z)
>>> $ declare -p A
>>> declare -a A=([0]="X=a b")
>> It's an assignment statement in a context where assignment statements are
>> accepted (which is what makes it different from `echo X=$Z', for instance),
>> but the lack of a subscript on the lhs makes it a special case. I'll take a
>> look at the semantics here.
> This is also a bit curious:
>  $ b=( [123]={a,b,c}x )
>  $ declare -p b
>  declare -a b=([0]="[123]=ax" [1]="[123]=bx" [2]="[123]=cx")
> It does seem to have a subscript on the LHS, but it didn't work as one.
> To be in line with a plain scalar assignment, the braces should probably
> not be expanded here.

Thanks, I'll look at it.

``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/

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