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Re: while clause with two conditions does not execute when continue is u
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From: |
Greg Wooledge |
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Subject: |
Re: while clause with two conditions does not execute when continue is used |
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Date: |
Wed, 21 Oct 2020 11:13:21 -0400 |
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User-agent: |
Mutt/1.10.1 (2018-07-13) |
On Wed, Oct 21, 2020 at 04:48:39PM +0200, rrd@beelaertsict.nl wrote:
> #!/bin/bash
> # test error in while clause
> #
> set -x
> up () {
> i=$(($i+1))
> [ $i -eq 5 ] && j=$(($j+1)) && i=0
> }
> while [ $i -ne 4 -o $j -ne 2 ]
> do
> if [ $i -eq 3 ]
> then
> up && continue
If $i is 3, you call up. up increments i, so $i is now 4. Then it
runs [ $i -eq 5 ] which is false, so the function returns false.
Therefore, continue is never executed here.