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Re: syntax error while parsing a case command within `$(...)'
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From: |
Lawrence Velázquez |
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Subject: |
Re: syntax error while parsing a case command within `$(...)' |
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Date: |
Sat, 13 Feb 2021 15:41:30 -0500 |
> On Sat, Feb 13, 2021, 21:34 Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com> wrote:
>
> you didnt end the case, wrong syntax
> echo $( case x in y) printf 1 ;; x) printf 2 ;; esac )
$ case x in x) esac
$ echo $?
0
> On Feb 13, 2021, at 3:36 PM, Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com> wrote:
>
> you have to specify something for <here>) even when its just a * wildcard
Oğuz did specify a pattern. It's the second 'x'.
vq
- syntax error while parsing a case command within `$(...)', Oğuz, 2021/02/13
- Re: syntax error while parsing a case command within `$(...)', Robert Elz, 2021/02/13
- Re: syntax error while parsing a case command within `$(...)', Robert Elz, 2021/02/14
- Re: syntax error while parsing a case command within `$(...)', Stephane Chazelas, 2021/02/14
- Re: syntax error while parsing a case command within `$(...)', Robert Elz, 2021/02/14