Re: Bash extended glob - Negation

[Oğuz]

30 Nisan 2021 Cuma tarihinde Robert Elz <kre@munnari.oz.au> yazdı:

>     Date:        Fri, 30 Apr 2021 12:28:32 +0530
>     From:        Inian Vasanth <inian.vasanth@gmail.com>
>     Message-ID:  <CADNZbLRBuvtihJC-EsY0NKeMsVibTKvgpQ33qve_g-yZ=R
> 3u_Q@mail.gmail.com>
>
>   | Why is it the case? Shouldn't the glob expression just serve the !(8)
>   | pattern to exclude and simply do a no-op for the extra * character?
>
> The '*' means "sero or more of the preceding", the preceding was
> "not an 8" so anything which ends with zero (or more) not 8's matches.


No, this isn't regex. `*' alone means zero or more of anything. What OP
doesn't understand here is that `!(8)' can match the empty string. A
simpler example would be:

$ touch a b c
$ echo !([ab])
c
$ echo !([ab])*
a b c


> Since everything ends with 0 (or more) not 8's (or not anything elses)
> everything matches.
>
> kre
>
>
>

-- 
Oğuz