Re: 'command' builtin doesn't seem to work for external 'printf'

[Carl Thompson]

Nevermind! I was misunderstanding what the 'command' builtin does!

Thank you,
Carl

>     On 5/17/2021 3:40 PM Carl Thompson <carl@carlthompson.net> wrote:
> 
> 
> 
>     Configuration Information [Automatically generated, do not change]:
>     Machine: x86_64
>     OS: linux-gnu
>     Compiler: gcc
>     Compilation CFLAGS: -march=x86-64 -mtune=generic -O2 -pipe -fno-plt 
> -DDEFAULT_PATH_VALUE='/usr/local/sbin:/usr/local/bin:/usr/bin' 
> -DSTANDARD_UTILS_PATH='/usr/bin' -DSYS_BASHRC='/etc/bash.b
>     ashrc' -DSYS_BASH_LOGOUT='/etc/bash.bash_logout' 
> -DNON_INTERACTIVE_LOGIN_SHELLS 
>     uname output: Linux clip 5.10.26-brunch-sebanc #1 SMP PREEMPT Wed Apr 7 
> 21:32:32 CEST 2021 x86_64 GNU/Linux
>     Machine Type: x86_64-pc-linux-gnu
> 
>     Bash Version: 5.1
>     Patch Level: 4
>     Release Status: release
> 
>     Description:
>         'command' builtin doesn't seem to work for external 'printf'. It 
> appears to use the builtin.
> 
>             ---------------------------------------------------
>             [cet@clip ~]$ printf
>             printf: usage: printf [-v var] format [arguments]
> 
>             [cet@clip ~]$ type -P printf
>             /usr/bin/printf
> 
>             [cet@clip ~]$ /usr/bin/printf
>             /usr/bin/printf: missing operand
>             Try '/usr/bin/printf --help' for more information.
> 
>             [cet@clip ~]$ command printf
>             printf: usage: printf [-v var] format [arguments]
>             ---------------------------------------------------
> 
>         I believe that running 'command printf' should yield the same result 
> as running '/usr/bin/printf'
> 
>     Repeat-By:
>     (See above)
>