Re: Issue declaring an array via a variable name

[Léa Gris]

Le 15/08/2021 à 02:45, Hunter Wittenborn écrivait :
> - declare -g "${variable}"=("world" "me")
> - declare -g ${variable}=("world" "me")
> - declare -g "hello"=("world" "me")

Invalid because the string "${variable}" cannot be assigned = the scalar 
("world" "me")

If you want to dynamically compose the declare arguments, it either need 
to be only a string or only variable=value(s)

So these work because the argument is a string

declare -g "$variable=( \"world\" \"me\" )"
declare -g "$variable"'=( "world" "me" )'

Be cautious with dynamic declare statements, because it is as insecure 
as eval. It will execute statements contained in variables.

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