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"trap" output from "if" statement redirected wrongly
From: |
Frank Heckenbach |
Subject: |
"trap" output from "if" statement redirected wrongly |
Date: |
Wed, 13 Apr 2022 14:58:30 +0200 |
Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -g -O2 -fstack-protector-strong -Wformat
-Werror=format-security -Wall
uname output: Linux mars 5.10.0-12-amd64 #1 SMP Debian 5.10.103-1 (2022-03-07)
x86_64 GNU/Linux
Machine Type: x86_64-pc-linux-gnu
Bash Version: 5.1
Patch Level: 16
Release Status: release
Description:
This script writes "foo" to bar rather than stdout as I'd expect.
It's triggered by the "if" statement (which doesn't even cause
running in a subshell, so it's not that).
#!/bin/bash
set -e
trap 'echo foo' 0
#false > bar # "foo" written to stdout correctly
if true; then false; else false; fi > bar # "foo" written to bar
- "trap" output from "if" statement redirected wrongly,
Frank Heckenbach <=