Re: executes statement after "exit"

[Chet Ramey]

On 4/15/22 12:57 PM, Frank Heckenbach wrote:

> Bash Version: 5.1
> Patch Level: 16
> Release Status: release
>
> Description:
>
> bash executes statement after "exit".
>
> Happens with or without "set -e".
>
> Doesn't happen with newline instead of ";".
>
> Similar to https://bugs.debian.org/819327, but perhaps not the same
> (as that one also happens with newline).
>
> #!/bin/bash
> : $((08 + 0)); exit
> echo "Should not get here."

It never executes `exit'.

The explanation in 
https://lists.gnu.org/archive/html/bug-bash/2022-04/msg00010.html applies here.

The arithmetic syntax error (invalid octal constant) results in a word
expansion error (the $((...)) ), which causes the shell to abort execution
of the current command (the command list) and jump back to the top level
to continue execution with the next command (echo).

> But I guess that's also prescribed by POSIX, right?

POSIX requires the shell to exit on a word expansion error, which bash does
in posix mode.

--
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/