Re: local/typeset/declare -p - outputs invalid declare -- -

[Chet Ramey]

On 11/16/22 12:12 PM, Emanuele Torre wrote:
> The 31f4d468b60eb27d768ef56d0a8b4982346465d9 commit on the devel branch,
> addressed this issue, but only partially:
>
>      bash-5.1$ ./bash --version |& head -n 1
>      GNU bash, version 5.2.9(6)-maint (x86_64-pc-linux-gnu)
>
>      bash-5.1$ ./bash -c 'a () { local -; local -p; declare -p -; typeset -p -; 
> local -p - ;}; a'
>      local -
>      declare -- -
>      declare -- -
>      local -
>
> `local -p -' no longer prints "declare -- -", but `declare -p -', and
> `typeset -p -' still do.

It doesn't matter. `local -' is the only way to save and restore the 
options; `declare -p -' and `typeset -p -' should have no special meaning.

--
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/