Re: set -e not working as expected with conditional operators

[Chet Ramey]

On 6/1/23 9:01 PM, rpaufin1 wrote:
> Consider the following script:
>
> #!/bin/bash
>
> f() {
>          ls missing-file 2> /dev/null
>          echo "test"
> }
>
> # 1
> (set -e; f); ret=$?
> if (( ret )); then
>          echo "failed"
>          exit 1
> fi
>
> # 2
> (set -e; f) || {
>          echo "failed"
>          exit 1
> }
>
> Running the block labelled '1' prints "failed" and returns 1 as the exit code, while 
> running the other block prints "test" and returns 0. However, the result should be the 
> same.

It should not. The manual lists the instances where the shell does not
exit if a command fails while -e is enabled, and and-or lists are one of
those.

--
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/