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Re: $((expr)) allows the hexadecimal constant "0x"
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From: |
Chet Ramey |
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Subject: |
Re: $((expr)) allows the hexadecimal constant "0x" |
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Date: |
Thu, 29 Jun 2023 16:13:37 -0400 |
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User-agent: |
Mozilla/5.0 (Macintosh; Intel Mac OS X 10.15; rv:102.0) Gecko/20100101 Thunderbird/102.12.0 |
On 6/29/23 1:17 PM, Steffen Nurpmeso wrote:
I now only wondered why you did not also mention the bash bug
$ echo $((0?2/0:7))
7
$ echo $((0?2**-1:7))
-bash: 0?2**-1:7: exponent less than 0 (error token is ":7")
Probably because it doesn't have anything to do with hex constants?
Thanks for reporting it, though.
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU chet@case.edu http://tiswww.cwru.edu/~chet/