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Re: (hd0,0) != first partition?


From: Jochen Hoenicke
Subject: Re: (hd0,0) != first partition?
Date: Mon, 16 Oct 2000 11:26:47 +0200 (MET DST)

On Oct 15, Jan Hilberath wrote:
> Hello!
> 
> I am using the grub 0.5.96 ext2fs disk image.
> 
> Curently i only have one primary partition on my harddisk. So i thought
> it would be the right way to boot my DOS with this commands:
> 
> rootnoverify (hd0,0)
> makeactive
> chainloader +1
> 
> But this gave me the following error message:
> 
> Error 22: no such partition
> 
> Instead the partition is identified as (hd0,3). Linux
> recognizes it as /dev/hda4 too. Is this right?

Using (hd0,3) is correct.  Your partition is at the forth entry in the
mbr, and grub doesn't skip empty entries when counting.  

> (booting with rootnoverify (hd0,3) works fine)
> 
> Maybe a geometry problem? 
> grub:  CHS: 1024/255/63
> linux: CHS: 1655/255/63

This is no problem.  You can't access more than 1024 cylinders with
the CHS method and a PC BIOS.

> grub> geometry (hd0)
> 
> drive 0x80: CHS = 1024/255/63, The number of sectors = 26587575, LBA
>    Partition num 3, Filesystem type is fat, partition type 0x6

Grub uses LBA, so it can access all 1655 * 255 * 63 = 26587575
sectors.

  Jochen



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