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Re: problem in $(call ...) [func_call()]
From: |
Paul D. Smith |
Subject: |
Re: problem in $(call ...) [func_call()] |
Date: |
Sun, 8 Jan 2006 17:36:41 -0500 |
%% Anand Avati <address@hidden> writes:
aa> i do read a changelog entry in 2002-04-28 telling that exp_count
aa> contains max number of recursive calls allowed. but i do not
aa> understand why $(CMD) gets set with exp_count=0 while $(call CMD)
aa> gets set with exp_count=EXP_COUNT_MAX.. shouldnt their expansion
aa> principles be the same?
No. $(call) functions can be recursive; in fact, some of the most
useful invocations of call are recursive.
aa> i am assuming the difference could be, for call, $1 could contain
aa> the CMD again, or something like that?
Sometimes; usually its the function definition that calls itself
recursively.
aa> even if exp_count > 0 is needed, EXP_COUNT_MAX is proving to be
aa> too big a value. I re-built make with setting exp_count=0 in
aa> func_call(), in the place where it was being set to EXP_COUNT_MAX
aa> [diff attached], and i found all the test cases i could build,
aa> worked.. do we really need exp_count > 0 there? could you show me
aa> an example Makefile where exp_count=<arbitrary number> `works' or
aa> `helps'.
If you look at the test suite in the functions/call test, the first one
will fail if you set this to 0.
--
-------------------------------------------------------------------------------
Paul D. Smith <address@hidden> Find some GNU make tips at:
http://www.gnu.org http://make.paulandlesley.org
"Please remain calm...I may be mad, but I am a professional." --Mad Scientist