[bug #40431] .SHELLFLAGS is passed to shell as single argument.

[Paul D. Smith]

Update of bug #40431 (project make):

                  Status:                    None => Duplicate              
             Open/Closed:                    Open => Closed                 

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Follow-up Comment #3:

First, having -e enabled by default for recipes is a requirement of the latest
POSIX spec.  GNU make by default adheres to the previous POSIX spec in this
respect, where -e was required to NOT be present.  I'm not willing to break
backward-compatibility in this way, even if POSIX doesn't care.  If you use
the .POSIX: pseudo-target to request POSIX-compatibility mode, then -e will be
enabled by default and you don't need to change .SHELLFLAGS.

Second, the behavior of .SHELLFLAGS with multiple options is correct in the
currently released version of GNU make (4.0):


$ cat Makefile
.SHELLFLAGS = -e -c
.ONESHELL :
all :
        false
        echo "OK"

$ make
false
echo "OK"
Makefile:4: recipe for target 'all' failed
make: *** [all] Error 1


Third, make's standard shell is /bin/sh, not bash.  The POSIX shell does not
support flags such as -o pipefail and when bash is invoked as /bin/sh, it does
not either:


$ /bin/sh -e -o pipefail -c "echo hi"
/bin/sh: 0: Illegal option -o pipefail


So, if you want to use bash features in your makefiles then you  must
specifically request bash as the shell:


$ cat Makefile 
SHELL = /bin/bash
.SHELLFLAGS = -o pipefail -e -c
.ONESHELL :
all :
        false | true
        echo "OK"

$ make
false | true
echo "OK"
Makefile:5: recipe for target 'all' failed
make: *** [all] Error 1


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