I want to compile objects in order of the writting: y.o z.o x.o .
The order of compiling x.o are different in below three cases.
I don't understand the difference.
x : y.o z.o x.o # compiles x.o last
$(CC) $^ -o $@ # with recipe
x : y.o z.o # compiles x.o last
x : y.o z.o x.o # compiles x.o first
My purpose is to keep my Makefile simple. With the patsubst function in
Makefile, I just put Makefile with my source files and need to do nothing.
It just compiles. But this is gone if the order of compiling matters.
x : $(patsubst %.c,%.o,$(wildcard *.c))
Thanks
---
# My Minimal Makefile for C, C++
# build shared library with -fPIC, -shared
CFLAGS = -Wall -Wextra -g # -O3 -fPIC # CXXFLAGS for .cpp
LDFLAGS = # -L../hello # -shared
LDLIBS = # -lhello
CPPFLAGS = -MMD -MP # -I../hello
#CC = $(CXX) # link with CXX for .cpp
# target name is basename of one of the source files
main : $(patsubst %.c,%.o,$(wildcard *.c)) # .cpp
-include *.d
clean : ; -rm -fr *.o *.d
.PHONY : clean