[bug #63359] patsubst messes up functions in replacement

[Paul D. Smith]

Update of bug #63359 (project make):

                  Status:                    None => Not A Bug              
             Open/Closed:                    Open => Closed                 
       Component Version:                     SCM => 4.4                    

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Follow-up Comment #1:

You are misunderstanding how expansion happens.

All the expansion of variables _inside_ the function happen first, before the
function is run.  So:

$(info $(patsubst %/c,$(notdir %),$(FOO)))


First the macros `$(notdir %)` and `$(FOO)` are expanded, giving this:

$(info $(patsubst %/c,%,a/b/c))


Note that `$(notdir %)` is `%` because it treats the pattern as the literal
character `%`.  Similarly:

$(info $(patsubst %/c,$(dir %),$(FOO)))

yields:

$(info $(patsubst %/c,.,a/b/c))

because `$(dir %)` yields `.`.

Instead, you want to apply the function to the `$(FOO)` variable, like this:

FOO = a/b/c
$(info $(patsubst %/c,%,$(FOO)))
$(info $(patsubst %/c,%,$(notdir $(FOO))))
$(info $(patsubst %/c,%,$(dir $(FOO))))



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