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Re: Method.equals() question
From: |
Archie Cobbs |
Subject: |
Re: Method.equals() question |
Date: |
Thu, 27 Feb 2003 20:56:40 -0800 (PST) |
Tom Tromey wrote:
> Archie> Howver, this contradicts the JDK 1.4 docs, which say that the
> Archie> method's return type must also be equal:
>
> Archie> Is this a classpath bug?
>
> Yes. Care to submit a patch?
Sure! See below... fortunately this vastly simplifies things :-)
> Maybe this changed from 1.3 to 1.4. I know a lot of changes like this
> are happening in preparation for the addition of generics.
>
> Could you see if this did change from 1.3? If so we can add an
> @specnote to explain the change.
It turns out the comparision has included the return type since JDK 1.2.
Thanks,
-Archie
__________________________________________________________________________
Archie Cobbs * Precision I/O * http://www.precisionio.com
--- classpath/classpath-0.05/vm/reference/java/lang/reflect/Method.java Wed Dec
18 02:28:29 2002
+++ /home/archie/jc/classpath/java/lang/reflect/Method.java Thu Feb 27
18:04:53 2003
@@ -144,57 +134,14 @@
/**
* Compare two objects to see if they are semantically equivalent.
* Two Methods are semantically equivalent if they have the same declaring
- * class, name, and parameter list. This ignores different exception
- * clauses or return types.
+ * class, name, parameter list, and return type.
*
* @param o the object to compare to
* @return <code>true</code> if they are equal; <code>false</code> if not
*/
public boolean equals(Object o)
{
- // Implementation note:
- // The following is a correct but possibly slow implementation.
- //
- // This class has a private field 'slot' that could be used by
- // the VM implementation to "link" a particular method to a Class.
- // In that case equals could be simply implemented as:
- //
- // if (o instanceof Method)
- // {
- // Method m = (Method)o;
- // return m.declaringClass == this.declaringClass
- // && m.slot == this.slot;
- // }
- // return false;
- //
- // If a VM uses the Method class as their native/internal representation
- // then just using the following would be optimal:
- //
- // return this == o;
- //
- if (o == null)
- return false;
-
- if (!(o instanceof Method))
- return false;
-
- Method m = (Method)o;
- if(!name.equals(m.name))
- return false;
-
- if(declaringClass != m.declaringClass)
- return false;
-
- Class[] params1 = getParameterTypes();
- Class[] params2 = m.getParameterTypes();
- if(params1.length != params2.length)
- return false;
-
- for(int i = 0; i < params1.length; i++)
- if(params1[i] != params2[i])
- return false;
-
- return true;
+ return this == o;
}
/**
Re: Method.equals() question, Brian Jones, 2003/02/27