Re: [Discuss-gnuradio] Python OOT Block Selectable Types

[Martin Braun]

You can definitely do that. Passing in some numeric or string value as
the type to your block and then mapping to the correct numpy type would
definitely work. Maybe you can even select numpy types from a GRC file,
not sure if a GRC enum will allow you to choose numpy types.

M

On 05/12/2016 03:16 PM, Richard Bell wrote:
> Martin,
> 
> I like the first idea. Would it be possible to create a new variable in
> the xml file that is assigned numpy.float32 when the user selects the
> float option, or is assigned numpy.complex64 when the user selects the
> complex option? Another words, I don't want the user to have to select
> the port type AND have to type in the python type of the port, that
> should be clear from the port type drop down selection. I'm just not
> sure how to work this in the xml file, or if its even possible.
> 
> Rich
> 
> On Thu, May 12, 2016 at 11:11 AM, Martin Braun <address@hidden
> <mailto:address@hidden>> wrote:
> 
>     You can either make this a block argument (i.e., you ask the user to
>     pass in numpy.float32 or whatever), or, to keep consistent with the C++
>     way of doing things, you can make a block argument called 'sizeof' and
>     then create a dict that maps sizes to numpy.<FOO> values, and use that
>     to set in_sig.
> 
>     M
> 
>     On 05/11/2016 02:04 PM, Richard Bell wrote:
>     > I've created a python based OOT block and I want to give the user the
>     > ability to select the input/output type. I know how to do this for C++
>     > based blocks, but I'm stuck on what to do with the python blocks
>     > signature, as it doesn't ask for the item_size like the C++ blocks
>     do. I
>     > have to give it something explicit like
>     >
>     > in_sig = [numpy.float32]
>     >
>     > How do I write the generic sig that depends on what the user
>     selected in
>     > GRC?
>     >
>     > Note: The algorithm in the body of this block doesn't change depending
>     > on type selected. It's a simple block.
>     >
>     > Thanks,
>     > Rich
>     >
>     >
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