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Re: the out_items of python block?
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From: |
Marcus Müller |
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Subject: |
Re: the out_items of python block? |
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Date: |
Wed, 23 Jun 2021 14:26:42 +0200 |
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User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:78.0) Gecko/20100101 Thunderbird/78.11.0 |
Hi liumaolin,
> ?0?2?0?2?0?2 def work(self, input_items, output_items):
> ?0?2?0?2?0?2?0?2?0?2?0?2?0?2 """example: multiply with constant"""
> ?0?2?0?2?0?2?0?2?0?2?0?2?0?2 for i in range(10) :
You can't do that: you need to make sure you've got at least 10 output items to
fill!
> return len(output_items[0])
Here you tell GNU Radio that you produced `len(output_items[0])` items, where
in reality
you produced 10, which might (and will) be less or more than
`len(output_items[0])`!
Best regards,
Marcus