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Re: How do I get a ] into a reg exp?
From: |
David Kastrup |
Subject: |
Re: How do I get a ] into a reg exp? |
Date: |
Thu, 14 Sep 2006 00:07:22 +0200 |
User-agent: |
Gnus/5.11 (Gnus v5.11) Emacs/22.0.50 (gnu/linux) |
Lennart Borgman <address@hidden> writes:
> Lennart Borgman wrote:
>>>>
>>>> (info "(emacs) Regexps")
>>>>
>>>> To include a `]' in a character set, you must make it the first
>>>> character. For example, `[]a]' matches `]' or `a'. To include a
>>>> `-', write `-' as the first or last character of the set, or put
>>>> it after a range. Thus, `[]-]' matches both `]' and `-'.
>>>>
>>>> To include `^' in a set, put it anywhere but at the beginning of
>>>> the set. (At the beginning, it complements the set--see below.)
>>>>
>>>>
>>> Thanks. That was a surprise.
>>
>> New surprise. I still can not get it to work. This is my actual search:
>>
>> (re-search-forward "'\\([][-+a-zA-Z~<>!;,:.'\"%/?(){}$^0|]\\)'" nil t)
>>
>>
>> The above version does not match [ -- in the parenthesis.
> But this one works:
>
> (re-search-forward "'\\([][+a-zA-Z~<>!;,:.'\"%/?(){}$^0|-]\\)'" nil t)
>
> The - must be last. Thanks again.
Yes, [-+ is an empty range, since the first character is larger than
the last.
--
David Kastrup, Kriemhildstr. 15, 44793 Bochum
Re: How do I get a ] into a reg exp?, David Hansen, 2006/09/13