> (seq-concatenate 'list (seq-subseq seq 0 n)
> (list element)> (seq-subseq seq n))
That returns a list, not the sequence. So inserting something into the sequence
makes it not a sequence anymore?
> We currently don't have any data-structure that can be efficiently
> modified in-place via push/pop (note that even lists don't qualify> because push/pop doesn't modify the list in place: they replace a list> with another without modifying any existing list (unless the PLACE is> the car/cdr of a list, of course, but that's a separate issue)).
Thanks, it's good to know.
Yuan.