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[O] Re: advice: how to export a list without exporting all entries
From: |
Nicolas |
Subject: |
[O] Re: advice: how to export a list without exporting all entries |
Date: |
Fri, 01 Apr 2011 18:26:27 +0200 |
Hello,
Eric S Fraga <address@hidden> writes:
> Nicolas <address@hidden> writes:
>> Eric S Fraga <address@hidden> writes:
>>> I would like to move to a system in which all the actions are numbered
>>> sequentially. At present, they are numbered sequentially within a list
>>> for each meeting. I would like to have a single list which grows over
>>> time. However, when I distribute the minutes of the latest meeting, I
>>> would like to only have those actions which are not yet complete listed
>>> in the document I circulate. The complication is that I want those
>>> actions that have actually been done still in the list but not exported.
>>> Is there any way to /comment/ out individual list items (whether bullet
>>> or enumerated) on export? I export typically to latex but this need not
>>> be a constraint. Simply putting [ ] versus [X] boxes on the items is not
>>> satisfactory as the list would be very long if all items were included in
>>> the export.
>>> Is there some hook that I can intercept that would enable this? Can I
>>> encapsulate individual list items into latex macros with the status of
>>> the [ ] or [X] boxes? I am more than happy to write latex code as
>>> required! Or even, at a push, elisp code...
>> I'm not sure to fully understand what you want, but couldn't you
>> delete-matching-lines toggled check-boxes in a copy of the original
>> buffer, and export that?
>>
>> Regards,
>
> Thanks for the suggestion. I think you did understand me and, yes, that
> would work, but only *if* each list entry were a single line.
> Unfortunately, I tend to fill my list paragraphs so that each item in
> the list is often several lines and, in fact, often several paragraphs
> (especially when it concerns minutes of a meeting and resulting
> actions). delete-matching-lines would delete the first line of a list
> entry only.
>
> I need to be able to "delete" whole list entries automatically based on
> their status, whether in a copy or during export.
Maybe the following functions might help you. Their docstring is explicit.
#+begin_src emacs-lisp
(defun esf-list-remove-if (predicate struct)
"Remove all items satisfying PREDICATE in STRUCT and in buffer.
PREDICATE is a function called with item position as argument.
The modified STRUCT is returned."
(let ((rev-struct (reverse struct))
res e)
(while rev-struct
(setq e (pop rev-struct))
(let ((item (car e)))
(if (funcall predicate item)
(delete-region item (nth 6 e))
(push e res))))
res))
(defun esf-clear-toggled-checkboxes ()
"Remove toggled check-boxes from list at point.
Move point at the end of the list."
(interactive)
(if (not (org-at-item-p))
(error "Not at a list item")
(let* ((struct (org-list-struct))
(end (copy-marker (org-list-get-bottom-point struct))))
(esf-list-remove-if (lambda (e)
(equal "[X]" (org-list-get-checkbox e struct)))
struct)
(goto-char end))))
#+end_src
Then, remove toggled checkboxes in an hook called just before list processing:
#+begin_src emacs-lisp
(add-hook 'org-export-preprocess-after-tree-selection-hook
(lambda ()
(goto-char (point-min))
(while (org-list-search-forward (org-item-beginning-re) nil t)
(esf-clear-toggled-checkboxes))))
#+end_src
Note that this solution doesn't handle nested lists (i.e. checkboxes in
lists inside a drawer itself in a list).
HTH,
Regards,
--
Nicolas
- [O] Re: advice: how to export a list without exporting all entries,
Nicolas <=