Re: [O] delete, add new row

[henry atting]

Jonathan Leech-Pepin <address@hidden> writes:

> I'm not sure as to the reason why it does so, but based on your
> example, the formula is referencing the specific cell itself, rather
> than the relative position of the cell.  If you change your formula to
> use a relative reference, it will continue to work even when you add,
> remove and move the rows.
>
> #+TBLFM: @2$3..@>$3=vmean(@address@hidden);%.1f 
> or
> #+TBLFM: @2$3..@>$3=vmean(@<<address@hidden);%.1f
> will both provide you with the result you seem to be looking for.  The
> former uses your (first) horizontal line as the starting point,
> whereas the latter uses the 2nd row from the top.
>
> Regards,
> Jonathan
>
> On Thu, Dec 1, 2011 at 12:42, henry atting <address@hidden> wrote:
>
>     Suppose I have this table:
>     
>     | month | expenses | average |
>     |-------+----------+---------|
>     |     1 |       20 |         |
>     |     2 |       30 |    25.0 |
>     |     3 |       40 |    30.0 |
>     #+TBLFM: @3$3..@>$3=vmean(@address@hidden);%.1f
>     
>     Then I want to delete the second row and add a new one at the
>     bottom.
>     If I do so I get `#ERROR' on every recalculation.
>     
>     | month | expenses | average |
>     |-------+----------+---------|
>     |     2 |       30 |  #ERROR |
>     |     3 |       40 |  #ERROR |
>     |     4 | 50       |  #ERROR |
>     #+TBLFM: @2$3..@>$3=vmean(@address@hidden);%.1f
>     
>     If I push the second row to the bottom the
>     result is as if the last row is still the second one.
>     
>     | month | expenses | average |
>     |-------+----------+---------|
>     |     2 |       30 |    30.0 |
>     |     3 |       40 |    30.0 |
>     |     1 |       20 |    20.0 |
>     #+TBLFM: @2$3..@>$3=vmean(@address@hidden);%.1f
>     

Ah, I see the problem; and thanks, it works fine now.

henry

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