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[O] Output result of source block to a file
From: |
Roger Mason |
Subject: |
[O] Output result of source block to a file |
Date: |
Wed, 05 Jun 2019 08:11:50 -0230 |
User-agent: |
mu4e 1.1.0; emacs 26.1 |
Hello,
I want to output the result of the evaluation of a (python) source block
to a (graphics) file and have a link to the file inserted in the buffer.
Here is the code:
#+begin_src python :results value file :file scaleplot02.pdf :exports results
:var data=test
import matplotlib.pyplot as plt
import csv
scale = []
lescale = []
cdscale = []
energy = []
leenergy = []
cdenergy = []
for row in data:
scale.append(float(row[0]))
energy.append(float(row[1]))
if int(row[2]) != 0:
lescale.append(float(row[0]))
leenergy.append(float(row[1]))
if int(row[3]) != 0:
cdscale.append(float(row[0]))
cdenergy.append(float(row[1]))
plt.plot(scale,energy, 'r+')
plt.plot(lescale,leenergy, 'go')
plt.plot(cdscale,cdenergy, 'bo')
plt.xlabel('scale')
plt.ylabel('energy (Ha)')
plt.title('Energy vs scale')
plt.legend()
plt.savefig(file)
print ("[[./%s]]" % file)
#+end_src
This is the error:
NameError: name 'file' is not defined
Obviously the syntax on the begin_src line is wrong, but what should it
be instead?
Thanks,
Roger
- [O] Output result of source block to a file,
Roger Mason <=
- Re: [O] Output result of source block to a file, stardiviner, 2019/06/05
- Re: [O] Output result of source block to a file, Roger Mason, 2019/06/06
- Re: [O] Output result of source block to a file, Roger Mason, 2019/06/06
- Re: [O] Output result of source block to a file, John Kitchin, 2019/06/06
- Re: [O] Output result of source block to a file, Roger Mason, 2019/06/07
- Re: [O] Output result of source block to a file, John Kitchin, 2019/06/07
- Re: [O] Output result of source block to a file, Roger Mason, 2019/06/08
- Re: [O] Output result of source block to a file, John Kitchin, 2019/06/08
Re: [O] Output result of source block to a file, Ken Mankoff, 2019/06/05