Re: How to install grub on fakeraid (raid 0) which spans 2 TB?

[Seth Goldberg]

Quoting Bruce Dubbs, who wrote the following on Thu, 24 Dec 2009:

> Seth Goldberg wrote:
> > On Dec 23, 2009, at 9:37 PM, Bruce Dubbs <address@hidden> wrote:
> >
> > > Seth Goldberg wrote:
> > >
> > > > While the BIOS call supports 48-bit LBA, the MBR partition table is 
> > > > limited to 32-bit LBA addresses for partition dimensions.  If you 
> > > > partition the disk with a GPT partition table, those limitations are 
> > > > removed, but GPT-partitioned disks aren't supported by XP (at least).
> > >
> > > Excellent point, but doesn't that mean a BIOS that supports LBA (which as 
> > > been around for many years) will support 2^18 TB?  I think my arithmetic 
> > > is correct, but please correct me if I misunderstand.
> >
> >   Assuming a 512-byte sector size, the total number of bytes is 2^9 * 2^48 
> > = 2^57 = 2^27 TB.
>
> Hi Seth,
>
> I thought you just said the usual partition table only supported 32 bits:
>
> 2^9 * 2^32 = 2^41 bytes or 2 TiB, give or take a byte.  :)
>
> 1K = 2^10
> 1M = 2^20
> 1G = 2^30
> 1T = 2^40
>
> I think 48 bits gives 2^17 TiB or 128 Pib (Petabytes).

  Woops :).  I was calculating the total possible addressable, not the total 
for the DOS partition table :).  Yes, your calculation looks right to me.

 --S