Re: apply

[Mikael Djurfeldt]

On 8/3/05, Aurelien Chanudet <address@hidden> wrote:
> Hi all,
> 
> Consider the following code :
> 
> guile> (define x '( (1 1) (2 2) (3 3) ))
> guile> (apply (lambda (a b c) (map list a b c) x)
> ((1 2 3) (1 2 3))
> 
> I can't figure out a concise an elegant way to achieve the same result
> using a lambda form that will work whatever the length of x. Any
> suggestion ?

Well, using a lambda form in the same way as above, it would be:

  (apply (lambda args (apply map list args)) x)

but it's simpler to do

  (apply map list x)

M