guile-user
[Top][All Lists]
Advanced

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

About continuation


From: z_axis
Subject: About continuation
Date: Wed, 24 Sep 2008 11:44:18 +0800

hi, friends
I have ever learned Lisp at colleage. and i like its elegant way to program. 
However i really do not understand the meaning and usgae of continuation :(

For example, the following code makes me a big head!

(define bar (lambda (bar) bar))
(define foox (lambda (foo) (display "@") foo))
(define fooy (lambda (foo) (display "*") foo))
(foox (call/cc bar) (fooy (call/cc bar)))

you will get "@address@hidden@address@hidden ................."

would you mind explain the code ? 


Sincerely!
                                
--------------
z_axis
2008-09-24






reply via email to

[Prev in Thread] Current Thread [Next in Thread]