Re: [Help-bash] use variable as array name

[Jesse Molina]

I found this to be helpful in regards to indirection:

http://wiki.bash-hackers.org/syntax/pe#indirection

ONE=1
VAR=ONE
echo ${!VAR}


On 1/3/15 18:14, Eduardo A. Bustamante López wrote:
> On Fri, Jan 02, 2015 at 08:15:08PM +0100, Phillip Sz wrote:
> > Hi,
> >
> > I want to use a variable as an array name, but I dont see a way to do
> > this. For example:
> >
> > namelength="$((address@hidden -1))"
> >
> > and now I want to replace "array" with for example $1.
> That's possible with namerefs:
>
> | address@hidden ~ % bash script
> | 2
> | address@hidden ~ % cat script
> | #!/bin/bash
> |
> | thearray=(foo bar baz)
> |
> | set -- thearray
> | typeset -n key="$1"
> |
> | namelength="$((address@hidden -1))"
> | echo "$namelength"
>
> Or you could do it with indirection, by creating a copy of the array. Something
> like:
>
> key="address@hidden" copy=("${!key}") address@hidden
> echo "$length"