Re: [Help-bash] need help running a command from a bash script

[Wood Peter]

Greg, Seth,

Thank you for the replies. That worked.

I can't believe I've never ran into this before:

foo=asdf
echo ' "$foo" '
echo " '$foo' "

Thanks,

-- Peter

On Mon, Aug 8, 2016 at 2:01 PM, Seth David Schoen <address@hidden>
wrote:

> Wood Peter writes:
>
> > mycommand --option "var date1='2016-01-01T04:00:00.000Z',
> > date2='2016-08-08T04:00:00.000Z'"
> >
> > I'd like to run this from a bash script where the date will be a
> variable:
> >
> > date1value=`date --date=yesterday +%FT00:00:00.000Z`
> > date2value=`date --date=yesterday +%FT23:59:59.000Z`
> > mycommand --option "var date1=$date1value,date2=$date2value"
> >
> > The above is not working because the single quotes are missing i.e.
> > date1='date1_value_goes_here'
> > Also I can't do date1='$date1value' either because $ can't be inside the
> > sigle quotes.
>
> You should be able to just run
>
> mycommand --option "var date1='$date1value',date2='$date2value'"
>
> The $ is not considered to be "inside the single quotes" in this case
> because, being quoted by the double quotes, they lose their special
> meaning to the shell (but are still literally passed through to
> mycommand).
>
> bash$ foo=bar
> bash$ baz=qux
> bash$ echo mycommand --option "var foo='$foo',baz='$baz'"
> mycommand --option var foo='bar',baz='qux'
>
> The space between "var" and "foo" was also escaped by the double quotes
> in this case, so that entire string will be provided as a single
> command-line parameter.
>
> --
> Seth David Schoen <address@hidden>      |  No haiku patents
>      http://www.loyalty.org/~schoen/        |  means I've no incentive to
>   8F08B027A5DB06ECF993B4660FD4F0CD2B11D2F9  |        -- Don Marti
>