Re: Setting variable with getopts

[Dennis Williamson]

On Mon, Aug 9, 2021, 10:47 AM hancooper <hancooper@protonmail.com> wrote:

> Have introduced an echo so I can print the variable arg.
>
> local shortopts="Vuhv:"
>   while getopts $shortopts arg; do
>     echo "arg: $arg"
>     case $arg in
>
> If I run the function the first time I get
>
> myfunc -p 28
> arg: p
> val, arg: p  ;  OPTARG: 28
> val: 28
>
> But if I run the function again, I get
>
> myfunc -p 12
> val: 1
>
> There seems to be some problem with the while loop.
>
> ‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐
> On Monday, August 9, 2021 2:48 PM, hancooper via <help-bash@gnu.org>
> wrote:
>
> > I am experiencing difficulties setting a variable `p` that is supposed
> to be set using getopts.
> >
> > status ()
> > {
> >
> > local val=1
> > local shortopts="Vuhp:"
> >
> > while getopts $shortopts arg; do
> > case $arg in
> >
> > ........................................................
> >
> > =========================================================
> >
> > ("V")
> > printf "%s\n" "V01 Jul 2021 Wk27"
> > return
> > ;;
> > ("u")
> > printf "%s\n" "-V, -u, -h"
> > printf "%s\n" "getopt-status --"
> > return
> > ;;
> > ("h")
> > printf "%s\n" "Description."
> > return
> > ;;
> > ("p")
> > val="$OPTARG"
> > printf '%s\n' "val, arg: $arg ; OPTARG: $OPTARG"
> > ;;
> > (:)
> > echo "Current argument value, OPTARG: -$OPTARG" >&2
> > echo "Must supply an argument to -$OPTARG" >&2
> > ;;
> > (?)
> > printf "%s" "Invalid option, OPTARG: $OPTARG"
> > ;;
> > esac
> > done
> > shift "$OPTIND"
> >
> > echo "val: $val"
> >
> > }
>
>
>


Add

local OPTIND

at the top of your function.

>