Sorting using two field separators

[tolugboji]

‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐

On Sunday, October 17th, 2021 at 5:40 PM, Daniel Mills <danielmills1@gmail.com> 
wrote:

> On Sun, Oct 17, 2021 at 1:19 PM tolugboji tolugboji@protonmail.com wrote:
>
> > ‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐
> >
> > On Sunday, October 17th, 2021 at 4:59 PM, tolugboji via help-bash@gnu.org
> >
> > wrote:
> >
> > > ‐‐‐‐‐‐‐ Original Message ‐‐‐‐‐‐‐
> > >
> > > On Sunday, October 17th, 2021 at 4:47 PM, Alex fxmbsw7 Ratchev
> > >
> > > fxmbsw7@gmail.com wrote:
> > >
> > > > maybe go a sideway, convert the filenames batchly into has-one-sep,
> > > >
> > > > then sort, then change back
> >
> > I can use awk to use two field delimiters. But this still requires a
> >
> > little tweak to
> >
> > handle possibility of newlines.
> >
> > find "$fdir" -type f -name "${fnam}-*.png" -print0 |
> >
> > awk -F'[-.]' '{print $(NF-1), $0}' |
> >
> > sort -znk 1,1 | cut -d ' ' -f2-
>
> A second separator isn't needed here anyway, sort will just go by the
>
> numbers and ignore the rest afterward.

Fantastic, did not know that.

"find" uses a null character.  Could one make the awk command know that?

   find "$fdir" -type f -name "${fnam}-*.png" -print0 |
     awk -F'[-.]' '{print $(NF-1), $0}' |
     sort -znk 1,1 | cut -d ' ' -f2-
   echo