Re: Check if file size greater than a small number?

[Alex fxmbsw7 Ratchev]

filename printing :

minsize() { < <( LC_ALL=C find "${@:2}"  -printf %p\\0%s\\0\\0 ) gawk -v
RS=\\0\\0 -v FS=\\0 -v min=$1 'BEGIN { while ( getline <"/dev/stdin" ) if (
++i && $1 <= min ) print $1 ; exit }' ; }

minsize <minsize> <find entry points>

On Thu, Mar 10, 2022 at 3:03 AM Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com>
wrote:

> lil correction, not printf 22 >22 , its printf 22 >2
>
> On Thu, Mar 10, 2022 at 3:02 AM Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com>
> wrote:
>
>> mkdir ttt
>> cd ttt
>>
>> >0 ; printf 1 >1 ; printf 22 >22 ; printf 333 >3
>>
>> minsize() { < <( LC_ALL=C find "${@:2}" -maxdepth 0  -printf %s\\n ) gawk
>> -v min=$1 'BEGIN { while ( getline <"/dev/stdin" ) if ( ++i && $0 <= min )
>> print ARGV[i] ; exit }' "${@:2}" ; }
>>
>> minsize 2 *
>>
>> >>>
>>
>> 0
>> 1
>> 2
>>
>> On Wed, Mar 9, 2022 at 6:10 PM Peng Yu <pengyu.ut@gmail.com> wrote:
>> >
>> >
>> https://stackoverflow.com/questions/5920333/how-can-i-check-the-size-of-a-file-using-bash
>> >
>> > I see things like the above that call an external program or cat all
>> > the file content to check the size of a file.
>> >
>> > But if my goal is just to know whether the file size is greater than a
>> > smaller (say 40). What is the most efficient way to do so in bash?
>> >
>> > --
>> > Regards,
>> > Peng
>>
>