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Re: print out all members of a list, v.1.0
From: |
David Kastrup |
Subject: |
Re: print out all members of a list, v.1.0 |
Date: |
Fri, 04 Mar 2011 12:06:23 +0100 |
User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/24.0.50 (gnu/linux) |
"Pascal J. Bourguignon" <pjb@informatimago.com> writes:
> Barry Margolin <barmar@alum.mit.edu> writes:
>> Emacs Lisp is mostly a reimplementation of MockLisp, the dialect that
>> was used in Gosling Emacs, which was the original inspiration for GNU
>> Emacs. It's also very much like MACLISP, the dialect that RMS had
>> been using for over a decade.
>>
>> So he didn't design his own language, he was basically sticking with
>> what he knew and liked.
>
> MacLisp probably. CL is inspired a lot from MacLisp too. But I've
> read that MockLisp was far from being a full lisp (as its name would
> imply), and that it was probably the reason why RMS had to write a new
> real lisp for his emacs.
I suggest you google for a bit of history about Stallman and Gosling
Emacs. Not being able to use Gosling Emacs/MockLisp any more even
though many contributions to it were _intended_ to be made freely
available was actually the reason for Stallman to stop believing in
universal goodness and create the GPL.
--
David Kastrup
- Re: print out all members of a list, v.1.0, (continued)
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/02
- Re: print out all members of a list, v.1.0, rusi, 2011/03/02
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/02
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/02
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/03
- Re: print out all members of a list, v.1.0, rusi, 2011/03/03
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/03
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/03
- RE: print out all members of a list, v.1.0, Drew Adams, 2011/03/03
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/04
- Re: print out all members of a list, v.1.0,
David Kastrup <=
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/04