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Re: Understanding dotimes skipping by 2
From: |
Van L |
Subject: |
Re: Understanding dotimes skipping by 2 |
Date: |
Fri, 28 Sep 2018 11:29:13 +1000 |
> the following code snippet is as follows:
> (setq l `(1 2 3 4 5 6 7 8 9 0))
> (1 2 3 4 5 6 7 8 9 0)
> ;; iterate through a list two elements at a time
> (let ((x 0))
> (dotimes (/ (length l) 2)
> (progn
> (insert (format "%s %s, " (nth x l) (nth (+ x 1) l)))
> (setq x (+ x 2)))))
>
> ;; and below are the results
> 1 2, 3 4, 5 6, 7 8, 9 0, nil nil, nil nil, nil nil, nil nil, nil nil, 2
>
> I'm confused about the output (nil etc...)which follow the expected numbers.
> could someone explain?
The first argument to dotimes needs a symbol to value binding at a guess.
The character l and 1 are too easy to confuse in reading you might want to
avoid that.
(setq q '(1 2 3 4 5 6 7 8 9 0))
(let ((x 0))
(dotimes (i (/ (length q) 2))
(progn
(insert (format "%s %s, " (nth x q) (nth (+ x 1) q)))
(setq x (+ x 2)))))
; 1 2, 3 4, 5 6, 7 8, 9 0,