Re: int/float binary conversion

[float_dublin]

Ulrich Eckhardt wrote:
> Lars Christian Jensen wrote:
>
> >    float f1 = 4.5;
> >    int i =    *((int*)&f1);
> >    float f2 = *((float*)&i);
> >
> >    printf("f1 = %f, i = 0x%08x, f2 = %f\n", f1, i, f2);
>
>
> You are using stupid, brute force casts to convert between totally
> unrelated objects and expect anything useful?
>
> Sorry, but what exactly is your problem? If you wanted to demonstrate that
> it is possible to write C++ programs that don't behave consistently (i.e.
> show different implementations of 'undefined behaviour'), fine, but we all
> knew that already.
>
> Uli

what undefined behavor? if sizeof(int)==sizeof(float) f1==f2 must be bit 
copied.

to Lars Christian Jensen:
the only reason it could differ, I think is sizeof(int)!=sizeof(float),
I have not been able reproducing the first bahavor (when f2 is 0). Can 
you please try this (on your's (GCC) 4.0.1 20050727 (Red Hat 4.0.1-5)) 
and post results:

#include <cstdio>
#include <cstdlib>

int main() {
   float f1 = 4.5f;
   char *i=(char*)malloc(4);
   *((float*)i) = *((float*)&f1);
   float f2 = *((float*)i);

   printf("f1 = %f, f2 = %f\n", f1,  f2);
   free(i);
   return 0;
}