Re: How to replace %output with #$output?

[Feng Shu]

Mekeor Melire <mekeor@posteo.de> writes:

> 2022-03-21 / 21:57 / me@tobias.gr:
>
>> Remove the quote after arguments (replace it with a plain LIST call) and add 
>> #~ before (modify-phases ...) to define a gexp.
>>
>> Untested example:
>>
>>     (arguments
>>       (list #:tests? #f ; no tests
>>              #:make-flags (list "CC=gcc")
>>              #:phases
>>              #~(modify-phases %standard-phases
>>                  (delete 'configure)
>>                  (add-after 'unpack 'patch-makefile
>>                    (lambda _
>>                      (substitute* "Makefile"
>>                        (("/usr/local")
>>                         #$output)))))))
>
> With these changes I get this error:
>
>       Wrong type to apply: "CC=gcc"

What about #~(list "CC=gcc") or '(list "CC=gcc") ?


>
>> So does hard-coding 'gcc' over using (cc-for-target).
>
> Yes, I would also prefer to use cc-for-target. But I wanted to simplify
> my code first. Because in order to use cc-for-target, I have to use
> backticks. If you have a suggestion for how to use both cc-for-target
> and #$output, let me know.
>
>> Very strong opinions on Scheme coding style, that boy.
>
> Please don't assume gender. But yes, you can refer to me with the "he"
> pronoun.

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