RE: $(if) feature in make 3.80?

[zartaj . majeed]

Found some clues to an answer in the source.
function.c has an EXPERIMENTAL block containing
the functions $(eq ...) and $(not ...). No $(and ...)
or $(or ...) though.

I suppose this would bring it in line with the forms
of the conditional directives.

For those familiar with function.c, how does the following
look:

/*
  string-boolean and operator
 */
static char *
func_and(char* o, char **argv, char *funcname)
{
  unsigned char *s;
  int result = 0;
  for(s = (unsigned char*)argv[0]; isspace(*s); ++s);
  if(*s)
    for(s = (unsigned char*)argv[1]; isspace(*s); ++s);
  result = *s;  
  o = variable_buffer_output(o, result ? "1" : "", result);
  return o;
}

/*
  string-boolean or operator
 */
static char *
func_or(char* o, char **argv, char *funcname)
{
  unsigned char *s;
  int result = 0;
  for(s = (unsigned char*)argv[0]; isspace(*s); ++s);
  if(!(*s))
    for(s = (unsigned char*)argv[1]; isspace(*s); ++s);
  result = *s;
  o = variable_buffer_output(o, result ? "1" : "", result);
  return o; 
}

Zartaj

-----Original Message-----
From: address@hidden [mailto:address@hidden
Sent: Friday, April 06, 2001 9:17 AM
To: address@hidden
Subject: $(if) feature in make 3.80?


Will $(if ...) get boolean operators in make 3.80? Something like:

$(if $(eq condition1, condition2), ...)
$(if $(and condition1, condition2), ...)
etc.

I have found $(if ...) to be a very useful function. I often use it
where a conditional directive could not work. But having a
conditional without other boolean functions makes it much harder
to use.

Thanks,
Zartaj

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